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White raven [17]
3 years ago
6

Given: QR = ST, QS = 5x + 17, RT = 10 - 2x, RS = 3 Find: QS and QT

Mathematics
1 answer:
spayn [35]3 years ago
7 0

Answer:

QS=12, QT=21

Step-by-step explanation:

QS=RT

5x+17=10-2x

x= -1

QS= 12

QS-RS=QR

QR=ST=9

QS+ST=QT

QT=22

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Answer:

B) 7.5 in3

Step-by-step explanation:

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10. Suppose you earn $7.25 per hour working part-time for a florist. What is the minimum number of hours you must work to earn a
UNO [17]
To make it like a simple, I'll make an equation. Let x be the number of hours because x represents unknown and we don't know the hours. Then your per hour is $7.25 right? so it would be x7.25. You want to know how many hours you will work so you can earn $125. The equation is simple as this x7.25 = 125.
All you have to do is divide the equation by 7.25 because that's your per hour.
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3 years ago
What is 2 plus 2 times 489829
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Find the distance between the two points.(-7,4/19) and (7,4/9)
Dafna1 [17]

Answer:

<h2>d=(14,0)</h2>

Step-by-step explanation:

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7 0
2 years ago
All about simulitious equations​
Korolek [52]

Answer:

On occasions you will come across two or more unknown quantities, and two or more equations

relating them. These are called simultaneous equations and when asked to solve them you

must find values of the unknowns which satisfy all the given equations at the same time.

Step-by-step explanation:

1. The solution of a pair of simultaneous equations

The solution of the pair of simultaneous equations

3x + 2y = 36, and 5x + 4y = 64

is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides

to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.

2. Solving a pair of simultaneous equations

There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a

single equation which involves the other unknown. The method is best illustrated by example.

Example

Solve the simultaneous equations 3x + 2y = 36 (1)

5x + 4y = 64 (2) .

Solution

Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation

6x + 4y = 72 (3)

Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:

6x + 4y = 72 − (3)

5x + 4y = 64 (2)

x + 0y = 8

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