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Anna007 [38]
3 years ago
8

Spermine (structure shown) is a compound isolated from sperm. Which of the following statements correctly describes an aqueous s

olution of spermine?
NH2(CH2)3NH(CH2)4NH(CH2)3NH2

Question 2 options:

A)

The hydroxide ion concentration in the solution would be greater than that in pure water.
B)

The hydronium ion concentration in the solution would be greater than that in pure water.
C)

The solution would be acidic.
D)

The pH of the solution would be equal to that of pure water.
Chemistry
2 answers:
Andru [333]3 years ago
5 0

Answer:

A) The hydroxide ion concentration in the solution would be greater than that in pure water.

Explanation:

Spermine has four amino groups. In water, these amino groups will be protonate -In NH₂⁺ or NH₃⁺- decreasing the H⁺ concentration and, by water equilibrium, increasing OH⁻ concentration.

Thus, in an aqueous solution of spermine <em>the hydroxide ion concentration in the solution would be greater than that in pure water.</em>

<em />

I hope it helps!

Mashcka [7]3 years ago
3 0

Answer:

The correct answer is option A)  The hydroxide ion concentration in the solution would be greater than that in pure water.

Explanation:

Spermine is basic in nature as it contains di-amine group (NH2), which is basic in nature that is, it easily gives off electrons.

Thus being basic spermine solution will have more concentration of Hydroxide ion [OH-].

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Answer:

oxidation, synthesis, polymerization

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Explanation:

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What pattern do you observe in the coefficients of the hydrocarbon (CxHy) and water (H2O)? How do you explain this pattern?
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The coefficients of the hydrocarbon and water is 61 and it is explained below.

Explanation:

We have to  balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2.  Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.

The unbalanced chemical equation is

C₈H₁₈ + O₂ → CO₂ + H₂O

To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by  8  to get  8  atoms of carbon on the products side.

C₈H₁₈ + O₂ → 8 CO₂ + H₂O

Now, we have 18  on the reactant side and  2  on the products side, so multiply the water molecule by  9  to get

C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O

8 * 2 atoms O + 9 *1 atoms O = 25 atoms O

By adding fractional coefficient to O₂ we get

C₈H₁₈ + \frac{25}{2}O₂ → 8 CO₂ + 9 H₂O

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2C₈H₁₈ + (\frac{25}{2} * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O

The balance equation is

2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

Add the coefficients to get their sum

= 2 +25 + 16 +18 = 61

Thus, The coefficients of the hydrocarbon and water is 61

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