Answer:
See explanation for details
Explanation:
ammonium sulfate and barium nitrate Answer
Ba2+(aq) + SO4^2-(aq) ----------> BaSO4(s)
lead(II) nitrate and sodium chloride Answer
Pb2+(aq) + 2Cl-(aq) -----------> PbCl2(s)
copper(II) chloride and sodium hydroxide Answer
Cu2+(aq) + 2OH-(aq) -------------> Cu(OH)2(s)
There can only be a net ionic reaction when a precipitate is formed as the two solutions are mixed together.
Answer:
Filled below
Explanation:
#v.e means number of valence electrons.
Also, the column total v.e is gotten by adding the v.e of the metal to the v.e of the non metal based on the chemical formula of both of the 2 elements combined.
K: Cl: 5; KCl; 1 + 5 = 6
Be: S: 6; BeS; 2 + 6 = 8
Na: F: 7; NaF; 1 + 7 = 8
Mg: Se: MgSe; 2 + 6 = 8
Al; N; AlN; 1 + 5 = 6
Be; F; BeF2; 2 + 2(7) = 16
Mg; N; Mg3N2; 3(2) + 2(7) = 20
Answer:
Explanation:
522 g
Explanation:
Your starting point here will be the balanced chemical equation for this combustion reaction
4
P
(s]
+
5
O
2(g]
→
2
P
2
O
5(s]
Notice that you have a
4
:
5
mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need
5
4
time more moles of oxygen gas.
Use phosphorus' molar mass to determine how many moles you have in that
93.0-g
sample
93.0
g
⋅
1mole P
30.974
g
=
3.0025 moles P
Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction
3.0025
moles P
⋅
5
moles O
2
4
moles P
=
3.753 moles O
2
<span>a. NaNO3: soluble
b. AgBr: insoluble
c. NH4OH: soluble
d. Ag2CO3: insoluble
e. NH4Br: soluble
f. BaSO4: insoluble
g. Pb(OH)2: soluble
h. PbCO3: insoluble</span>
