Speed of the ship in the second hour = (62.5 * x ) / 100 kph.
In third hour it is [(62 * x) / 100 ] * x/100]
is 4th hour its is the above * x/100 again so we can now form the equation
62.5x x x
------- * ---- * ---- = 32
100 100 100
62,5 x^3 = 32,000,000
x^3 = 512,000
x = 80 <----- Answer to (a)
(b) Ship travels 62.5 in first hour then this falls by a common ratio of 0.8 each hour so we have a geometric sequence
Dist travelled in 6 hours = a1 1 - r^n
-------- = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56
1 - r
Answer is 230.56 km
Step-by-step explanation:
This can be put into fractions like this
Say x is the length of the missing dimension
8.5/11 = 10.5/x
Because the 2 drawings are SIMILAR, the ratio of their side lengths has to also be the same
8.5 ÷ 10.5 = 0.8095
11 × 0.8095 = 8.9047
Roung the answer to the nearest tenth
x = 8.9 in
Answer: X = 7√2
Step-by-step explanation:
Let first Consider triangle BDC,
Cos C = adjacent/ hypothenus
Cos C = 7 / x ...... (1)
Also, let consider triangle ABC
Cos C = adjacent / hypothenus
Cos C = x / 14 ....... (2)
Since angle C is the same, equate equation 1 to 2
7/ x = x / 14
Cross multiply
X^2 = 98
Make x the subject of formula
X = sqrt (98)
X = sqrt ( 49 × 2 )
X = sqrt (49) × sqrt (2)
X = 7 sqrt(2)
X = 7√2
1+sin²x=2-cos²x
Remenber: sin²x+cos²x=1 ⇒sin²x=1-cos²x
1+sin²x=1+(1-cos²x)=2-cos² x (this is true)
