A 40% chance
Unless!
*wispers*
It’s a trick question?
Since the area of a circle is π

, and our radius is 9 we know the total area to be 254.469, and the ratio of sector area to total area is 169.56/254.469 = .6663. There are 360 degrees in a circle, so:

≈ 240°
240 degrees
For any equation,

assume solution of a form, 
Which leads to,

Simplify to,

Then find solutions,

For non repeated real root y, we have a form of,

Following up,
For two non repeated complex roots
where,

and,
the general solution has a form of,

Or in this case,

Now we just refine and get,

Hope this helps.
r3t40
A compound inequality is a sentence with two inequality statements joined either by the word “or” or by the word “and.” “And” indicates that both statements of the compound sentence are true at the same time.
“Or” indicates that, as long as either statement is true, the entire compound sentence is true.
Now as shown in the graph, the solution inequality of the graph is :
x > 3 and x < 5 [please note, circles in the graph indicate exclusion, dots indicate inclusion. in the graph given circles are shown, so it depicts exclusion]
Now let's solve each option to find if it fits in with the above inequality
Option 1 : 2x-4 > 6 or 3x < 9
⇒ x > 5 or x < 3
Option 2 : 2x - 4 < 6 and 3x > 9
⇒ x < 5 and x > 3
Option 3 : 3x + 8 > -7 or -4x < 12
⇒ 3x > -15 or x < -3
⇒ x > -5 or x < -3
Option 4 : 3x + 8 < -7 and -4x > 12
⇒ 3x < -15 and x > -3
⇒ x < -5 and x > -3
So the compound sentence in option 2 : 2x - 4 < 6 and 3x > 9
has its solution set on the graph.