<h2>Question :</h2>
<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>
<h2>Answer :</h2>
<em>y = -3/2x - 4 </em>
<h2>Explanation :</h2>
y = mx + c
*m = gradien
•>looking for gradients
y=2/3x+9
m1 = 2/3
m2 = -3/2
•>line equation (-6,5)
y - y1 = m(x - x1)
y - 5 = -3/2(x - (-6))
y - 5 = -3/2(x + 6)
y - 5 = -3/2 - 9
y = -3/2x - 9 + 5
y = -3/2x - 4
By inspection, it's clear that the sequence must converge to

because

when

is arbitrarily large.
Now, for the limit as

to be equal to

is to say that for any

, there exists some

such that whenever

, it follows that

From this inequality, we get




As we're considering

, we can omit the first inequality.
We can then see that choosing

will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that

.
Down payment is 20% of the price of the home. Since the couple saved $35,000, and assuming they will pay the whole money as down payment, the highest priced home they can get is a price whose 20% is $35,000.
We can setup an equation in x (being the price of home) to get the price of the most expensive home they can buy.
<em>Which number (x) , multiplied by 20%, is equal to $35,000?</em>
<em>
</em>
So, the most expensive house they can buy is worth $175,000.
ANSWER: $175,000
think the answer is
x=6+sqrt0/2 x=6-sqrt0/2 both equaling into 3.
But I might be wrong.