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Mama L [17]
4 years ago
11

The product of two consecutive positive even integers is 14 more than their sum. Set up an equation that can

Mathematics
1 answer:
Nana76 [90]4 years ago
3 0

Answer:

<em>The numbers are 4 and 6</em>

<em />

Step-by-step explanation:

Let

x------>  be the first positive even integer

x+2---> be the second positive even integer

<em>we know that the solution is a positive value</em>

<em />

<u>The numbers are 4 and 6</u>

Hope this helps!

<em>stay safe</em>

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What are the answers
Drupady [299]
1: 9x^3y^4

2: 6x^5y^4
6 0
3 years ago
ਇਕ ਐਕਸੈਲ ਵਰਕਬੁੱਕ ਵਿੱਚ ਹੁੰਦੀਆ ਹਨ<br> ​
kompoz [17]

Answer:

Cannot understand, please translate

Step-by-step explanation:

5 0
3 years ago
Which expression is equivalent to 4√24x∧6y÷ 128x∧4y∧5
LenKa [72]

Answer:

Option D.  \sqrt[4]{\frac{3x^{2}}{2y}}

Step-by-step explanation:

\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}

\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}

= \sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}

= \sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}

= \sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}

= \sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}

= \frac{y^{-1}}{2}\sqrt[4]{3x^{2}}

= \sqrt[4]{\frac{3x^{2}}{2y}}

Option D. \sqrt[4]{\frac{3x^{2}}{2y}}  is the correct answer.

5 0
4 years ago
Please help with this question I will give BRAINLIEST to the person that answers correctly
Minchanka [31]
It would 144 sq ft

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50*2=100
100+44=144
3 0
3 years ago
Read 2 more answers
Enter the solutions from least to greatest. -2x^2 -9=-107
ASHA 777 [7]

Answer:

x = -7, 7

Step-by-step explanation:

Step 1: Write out equation

-2x² - 9 = -107

Step 2: Add 9 on both sides

-2x² = -98

Step 3: Divide both sides by -2

x² = 49

Step 4: Square root both sides

x = ±7

Step 5: Arrange

-7 < 7

So x = -7, 7

3 0
4 years ago
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