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Komok [63]
3 years ago
13

HELP PLEASE

Mathematics
1 answer:
Drupady [299]3 years ago
6 0
Its A because if you use 9 cms, and times or divide you will get thoes, its all about converting. 
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Y - 6 = 4(1 - 4)
klasskru [66]

y - 6 = 4(1 - 4)

y - 6 = 4 - 16

y - 6 = -12

y = -12 + 6

y = -6

This is a horizontal line through the point (0, -6). See below.

4 0
3 years ago
Terrence McGraw sells lumber. He earns 4% commission on the first $5,000 in sales, 8% on the next $5,000, and 12% on sales over
Sindrei [870]
His total commission was $1560.
5 0
3 years ago
The parents' club will need 100 of the same item for international night. They have a budget of $250. The choices are 100 baseba
Nuetrik [128]

Answer:

The parents' club can afford to buy 100 Baseball hats or 100 sports bottles.

Step-by-step explanation:

Given:

Item to be bought = 100

Total Budget = $250

Cost of each Baseball Hat = $2.45

Cost of each sports bottles = $2.50

Cost of each flag = $2.75

We need to find which items can they afford to buy.

Solution:

each Baseball Hat = $2.45

100 Baseball Hat = Cost of 100 Baseball Hat

Using Unitary method we get;

Cost of 100 Baseball Hat  = 2.45\times 100 =\$245

each sports bottles = $2.50

100 sports bottles = Cost of 100 sports bottles

Using Unitary method we get;

Cost of 100 sports bottles  = 2.5\times 100 =\$250

each flag = $2.75

100 flags = Cost of 100 flags

Using Unitary method we get;

Cost of 100 flags  = 2.75\times 100 =\$275

Hence from above we can see that;

Cost of 100 Base ball hat and 100 sports bottles are within the budget while Cost of 100 flags exceed the budget.

So we can say that;

The parents' club can afford to buy 100 Baseball hats or 100 sports bottles.

6 0
3 years ago
Give an example of an addition problem in which you would and would not group the addends differently to add
madam [21]
<span>Changing the grouping of the addends should not change the sum, according to the associative property of addition. You might group them differently with (50 + 3) + 47, so that you have 50 + (3 + 47). You might not regroup them with (16 + 4) + 5 rather than 16 + (4 + 5).</span>
8 0
3 years ago
Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
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