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weeeeeb [17]
4 years ago
13

4.44 x 4 = please my sister needs it

Mathematics
1 answer:
Ludmilka [50]4 years ago
6 0

Answer:

17.76

Step-by-step explanation:

0.44 x 4 = 1.76

4 x 4 = 16

16+1.76=17.76

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What is the difference between no solution and no real solution? When do you get multiple solutions? This is for solving absolut
Dmitriy789 [7]
No solution<span> would mean that there is </span>no<span> answer to the equation. It is impossible for the equation to be true </span>no<span> matter what value we assign to the variable. Infinite</span>solutions<span> would mean that any value for the variable would make the equation true.</span>No Solution<span> Equations.

</span>In other words, it "discriminates" between the possible solutions<span>. The discriminant is the expression found under the square root part of the quadratic formula (that is, . The value of tells how many </span>solutions<span>, roots, or x-intercepts the quadratic equation will have. If , there are two </span>real solutions<span>.</span>
8 0
3 years ago
Diego was trying to write (5^2)^4 with a single exponent and wrote (5^2)^4=5^2+^4=5^6. What should the answer be? Explain Diego'
o-na [289]

Answer:

5^8

Step-by-step explanation:

Diego added the exponents. This was an error. If he was simplifying

5^2 × 5^4, then he could add the exponents and get a correct answer. But his problem had a power raised to a power. In this case, you multiply the exponents to simplify.

(5^2)^4 means

5^2×5^2×5^2×5^2

which is

5×5×5×5×5×5×5×5

which is 5^8.

4 0
3 years ago
10 points to whoever answers this CORRECTLY and QUICKLY. Thanks
Ainat [17]
1 solution 

x = -1/2

-------------------------------------
4 0
3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Pavel [41]

\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Explanation:</h2>

Using the quadratic formula:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

8 0
3 years ago
16e^2-88e+121<br> pls help me
Rufina [12.5K]

Step-by-step explanation:-8.8e +122

7 0
4 years ago
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