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cupoosta [38]
4 years ago
9

CAN SOMEONE PLEASE HELP ME??? THIS ANSWER IS NOT PROPERLY SELECTED...IT WAS CLICKED ON BY ACCIDENT...PLEASE DO NOT CHEAT OR LIE

WHEN ANSWERING..THANKS :)

Mathematics
2 answers:
zhannawk [14.2K]4 years ago
7 0

Answer:

The answer is Option B

Step-by-step explanation:

<u>Step 1:  Find the points</u>

The leftmost point is:  <em>(-3, -1)</em>

The next point is:  <em>(-2, 2)</em>

The next point is:  <em>(1, 0)</em>

The next point is:  <em>(3, 1)</em>

The rightmost point is: <em> (4, -2)</em>

<em />

Answer:  The answer is Option B

Helga [31]4 years ago
4 0

Write the location of each black dot:

(-3,-1) (-2,2) (0,1) (3,1) (4,-2)

The answer is the second choice.

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HELP PLSSSSS AAAAAAAAAAAAAAAAAAAAAA ILL GIVE BRAINLIEST B(
CaHeK987 [17]

Answer:

a(n) = (3/5)a(n-1), where a(1) = 10 and n is 2 or greater.

Step-by-step explanation:

determine the common factor...The first term (10) by 3/5 results in the given second term (6); the third term is 3/5 of the second term (6), resulting in 18/5 (equivalent to 36/10 or 3.6/1, or just 3.6. Resulting in a(n) = (3/5)a(n-1).

the third term is 3.6, which, if mult. by (3/5), produces 2.16, as expected.

Thus, the recursive formula for this geometric sequence is a(n) = (3/5)a(n-1).

This is good only for a(1) = 10 and n = 2, 3, ....

Hope this helps you

3 0
4 years ago
Help please I have a black mother who WILL use the belt!!! 80% of the students voted for John as class
Ierofanga [76]
Is that all the info ? If so say 128 voted
5 0
4 years ago
A farmer paid$1870 for 11 cutlasses.He then sold them to make a profit of 40% .calculate the selling price for each cutlasses
garik1379 [7]

1800

Step-by-step explanation:

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6 0
3 years ago
Please help!! 10 points
hichkok12 [17]

Answer:

We conclude that:

\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}

Hence, option B is correct.

Step-by-step explanation:

Given the expression

\sqrt[3]{200k^{15}}

Apply radical rule:

\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

so the expression becomes

\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}

first solving

\sqrt[3]{k^{15}}

Apply radical rule: \sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0

\sqrt[3]{k^{15}}=k^{\frac{15}{3}}=k^5

then solving

\sqrt[3]{200}

prime factorization:  200:  2³ · 5²

=\sqrt[3]{2^3\cdot \:5^2}

Apply radical rule:

\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

=\sqrt[3]{2^3}\sqrt[3]{5^2}

Apply radical rule:  

\sqrt[n]{a^n}=a,\:\quad \:a\ge 0

so

=2\sqrt[3]{5^2}

Thus, the main expression becomes

\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}

              =2k^5\sqrt[3]{25}

Therefore, we conclude that:

\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}

Hence, option B is correct.

3 0
3 years ago
Which relationships describe angles 1 and 2?
attashe74 [19]

Answer:

adjacent angles and complementry

Step-by-step explanation:

I think

3 0
2 years ago
Read 2 more answers
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