When y=2 and y=5
1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15
----nonequivalent-----
2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then
-----equivalent------
and no need to find more
29
2x29=58-3 =55
3-2x (x=29) =55
29x2=58-3
The answer you already have selected in the image is correct. Even eyeballing it, you can see that the smaller shape fits into the larger shape 4 times.
Bring the shape on the other side of the y axis. A mirror image.
It will be on the top right. That is quadrant 1
