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2 years ago

Using the drawing, how would you classify angles 9 and 10?

Mathematics

1 answer:

Marat540 [252]2 years ago

3 0

That would be D. Adjacent because they share a side.

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Elena has bought 320 tropical fish for a museum display. She bought 7 times as many triggerfish as parrotfish. How many of each

STALIN [3.7K]

The total number of fish bought was 320. And you know she bought two types of fish. The best way to solve this is guess and check. It would be the fastest. So she bought 7 times as many trigger-fish as parrot fish that means the number of trigger-fish bought was 7p. This means 320 = 7p +p. So all you do is take educated guesses for the number of parrot fish and check if it is right. So if she bought 50 parrot fish. 7(50) + 50 = 400. Close but a bit high. Lets keep guessing. 7(35) + 35 = 245. So now we know the answer is between 50 and 35. So lets try 40. 7(40) + 40 =320. That works so we know she bought 40 parrot fish and 280 trigger-fish.

8 0

2 years ago

Please I need help asap.

sukhopar [10]

Answer:

i cant see the question really well,can you plz send another copy

Step-by-step explanation:

8 0

2 years ago

In each of these situations light refracts, except for one. Identify the case in which light is NOT refracted.

Eva8 [605]

B) sunlight travels through space - there is nothing to bounce off of until it hits an atmophere

3 0

2 years ago

Read 2 more answers

What is the answer to his question

horsena [70]

Answer:

A. 720 per hour

Step-by-step explanation:

1200+ 720 + 720 + 360 =3000

hr 1↑+ hr 2↑ + ↑30 min

8 0

3 years ago

The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard d

skelet666 [1.2K]

Answer:

$z=-0.842$

And if we solve for a we got

$a=30 -0.842*7.8=23.432$

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.

Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(30,7.8)$

Where $\mu=30$ and $\sigma=7.8$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.80$ (a)

$P(X$ (b)

As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=30 -0.842*7.8=23.432$

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.

8 0

3 years ago