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4 years ago

Please help me with this and explain how you do this. U have to simplify each expression simplify variables expressions

Mathematics

1 answer:

neonofarm [45]4 years ago

6 0

1. 3(9k-4) - 4( 5n-3)

2. 3(5k)-4(5n-3)

3. 3(5k) -4(2n)

4. 15k-8n

Hope that helps.

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faust18 [17]

Answer:

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3 years ago

2.The mean area of several thousand apartments in a new development is advertised to be 1,100 square feet. A consumer advocate h

KiRa [710]

Answer:

Null Hypothesis, $H_0$ : $\mu$ = 1,100 square feet

Alternate Hypothesis, $H_A$ : $\mu$ < 1,100 square feet

Step-by-step explanation:

We are given that the mean area of several thousand apartments in a new development is advertised to be 1,100 square feet.

A consumer advocate has received numerous complaints that the apartments are smaller than advertised.

Let $\mu$ = mean area of several apartments.

So, Null Hypothesis, $H_0$ : $\mu$ = 1,100 square feet

Alternate Hypothesis, $H_A$ : $\mu$ < 1,100 square feet

Here, null hypothesis states that the mean area of apartments are same as advertised.

On the other hand, alternate hypothesis states that the mean area of apartments are smaller than advertised.

So, this would be the appropriate null and the alternative hypothesis to test this claim.

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3 years ago

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xenn [34]

Answer:

7.5%

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86 - 80 / 80 = 0.075

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8 0

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