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Tems11 [23]
3 years ago
12

Tryyyyy hardddddd!!!!!!!!!!

Mathematics
2 answers:
Greeley [361]3 years ago
7 0

Answer:

Step-by-step explanation:

980

aalyn [17]3 years ago
4 0
8,700 books had minor damage
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Dawson practices soccer for 30 minutes each weekday the expression 30x can be used to find the total number of minutes Dawson ha
Mandarinka [93]

Answer:

How many days he practiced I would assume.

Step-by-step explanation:

As an example lets say he practiced for 3 days then it would be 30(3) and that would add up to 90 mins, so yea how ever many days he practiced is X.

x=days practiced  

6 0
3 years ago
Find the area of a floor that measures 12.75ft. by 10.5ft.
babymother [125]

Answer:133.875ft^2

Step-by-step explanation:

Area=length×breadth

Area=12.75×10.5

Area=133.875ft^2

5 0
4 years ago
How to find missing endpoint?
Ainat [17]
You can determine the distance between the known 'endpoint' to the 'midpoint' then work the same change on midpoint 
8 0
3 years ago
Read 2 more answers
20 points, please answer quickly.
erica [24]

Measurement of angle 2 = 34 degrees

Here angle 2  and 4  are vertically opposite angles

Vertically opposite angles are always equal.

In the given figure 1  and 3 are vertically opposite angle . Also 2  and 4 are vertically opposite angles. So they are same

angle 2 = angle 4

∠2 = ∠4

34=∠4

Angle 4 = 34 degrees

4 0
3 years ago
Match the equations representing parabolas with their directrixes. y + 8 = 3(x + 2)2 y − 14 = -(x − 3)2 y + 7.5 = 2(x + 2.5)2 y
Shkiper50 [21]

Answer:

Part 1) y+8=3(x+2)^{2} -----> y=-8.08

Part 2) y-14=-(x-3)^{2} ---->  y=14.25

Part 3) y+7.5=2(x+2.5)^{2} ---->  y=-7.625

Part 4) y-17=-(x-3)^{2} -----> y=17.25

Part 5) y+7=(x-4)^{2} ----> y=-7.25

Part 6) y-6=-(x-1)^{2} ---->  y=6.25

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

y-k=\frac{1}{4p}(x-h)^{2}

where

(h,k) is the vertex

The directrix is

y=k-p

case 1) we have

y+8=3(x+2)^{2}

the vertex is the point (-2,-8)  

\frac{1}{4p}=3

p=\frac{1}{12}

The directrix is equal to

y=-8-\frac{1}{12}=-8.08

case 2) we have

y-14=-(x-3)^{2}

the vertex is the point (3,14)  

\frac{1}{4p}=-1

p=-\frac{1}{4}

The directrix is equal to

y=14+\frac{1}{4}=14.25

case 3) we have

y+7.5=2(x+2.5)^{2}

the vertex is the point (-2.5,-7.5)    

\frac{1}{4p}=2

p=\frac{1}{8}    

The directrix is equal to

y=-7.5-\frac{1}{8}=-7.625

case 4) we have

y-17=-(x-3)^{2}

the vertex is the point (3,17)      

\frac{1}{4p}=-1

p=-\frac{1}{4}    

The directrix is equal to

y=17+\frac{1}{4}=17.25

case 5) we have

y+7=(x-4)^{2}

the vertex is the point (4,-7)      

\frac{1}{4p}=1

p=\frac{1}{4}    

The directrix is equal to

y=-7-\frac{1}{4}=-7.25

case 6) we have

y-6=-(x-1)^{2}

the vertex is the point (1,6)      

\frac{1}{4p}=-1

p=-\frac{1}{4}    

The directrix is equal to

y=6+\frac{1}{4}=6.25

5 0
3 years ago
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