MN = 6 in
add the parts of the ratio, 1 + 2 + 3 = 6
divide AB by 6 to find 1 part of the ratio
= 3 ← 1 part
AM = 3 in ← 1 part
MN = 2 × 3 = 6 in ← 2 parts
NB = 3 × 3 = 9 in ← 3 parts
and 3 + 6 + 9 = 18 in = AB
Answer:
8x^2 - 2xy + 3y^2
Step-by-step explanation:
Use the FOIL method
8x^2 + 4xy - 6xy + 3y^2
8x^2 - 2xy + 3y^2
Answer:
vertical
Step-by-step explanation:
just need yo imagine
Answer:
Hold on, our servers are swamped. Wait for your answer to fully load.
more ponits not fair
Step-by-step explanation:
jus beig ismapHold on, our servers are swamped. Wait for your answer to fully load.


You changed the mixed numeral into a fraction correctly.
Now you need to multiply the fractions.
Multiply the numerators together, and multiply the denominators together.

Now we could multiply out the numerator and denominator, and then we'd need to reduce the fraction, but before we multiply, we see there is a factor of 5 both in the numerator and in the denominator, so we can reduce before we multiply.

