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Lostsunrise [7]
4 years ago
6

14 > 5(1 - x) + 2 (x +3)

Mathematics
2 answers:
kupik [55]4 years ago
4 0
14  \geq  5(1 - x) + 2 (x +3) \\ \\ 14 \geq 5-5x+2x+6 \\  \\14 \geq 11-3x\\ \\3x \geq 11-14 \\ \\3x \geq -3 \ \ /:3 \\ \\x \geq -1\\ \\x \in
Anastasy [175]4 years ago
3 0
14 \geq 5(1 - x) + 2 (x +3)\\
14\geq5-5x+2x+6\\
3x\geq-3\\
x\geq-1
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Step-by-step explanation:

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3 years ago
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PtichkaEL [24]
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I need help with this question
zvonat [6]

Answer:

Option B is correct

Step-by-step explanation:

Given:

f(x) = -20x^2 +14x +12 and

g(x) = 5x - 6

We need to find f/g and state its domain.

f/g = -20x^2 +14x +12/5x - 6

Taking -2 common from numerator:

f/g = -2(10x^2 - 7x - 6) / 5x -6

Factorize 10x^2 - 7x - 6= 10x^2 - 12x +5x -6

Putting in the above equation

f/g = -2(10x^2 - 12x +5x -6)/ 5x -6

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f/g = -2 ( (2x+1)(5x-6))/5x-6

cancelling 5x-6 from numerator and denominator

f/g = -2(2x+1)

f/g = -4x -2

The domain of the function is set of all values for which the function is defined and real.

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8 0
3 years ago
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4 0
4 years ago
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