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tresset_1 [31]
3 years ago
9

Round 0.433 to nearest tenths

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

0.433 is rounded to the hundredths already, so to round it to the nearest tenths, just remove the last number.

Your answer is going to be 0.43
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Please Explain How To Solve This
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Answer:

Step-by-step explanation:

domain is always the x-values, the first number of an ordered pair. and yes, the x and y values increase at a constant rate.

problem #1:

x   /   y

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problem #4:

(5, 1) (6, 2) (7, -3) (8, 4) (9, 5)

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3 years ago
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PLEASE HELP ASAP I’LL MARK BRAINLIEST Find the area of the figure.
Sonbull [250]
Area of a semicircle is 1/2* πr^2
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3 years ago
The solution set for the equation x - 6x + 10 = 0 is
Oxana [17]

Answer:

{3-i, 3+ i}

Step-by-step explanation:

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Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
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