6.15 divided by 31 rounded

Which expresses 216:270 in its simplest form

NeX [460]

<span>216:270 = 4:5

divide top and bottom by 54
hope it helps</span>

5 0

2 years ago

at the end of his shift, Bruno had $340 worth of tips all in $10 and $20 bills .if he had two more $20 bills than $10 bill .how

PSYCHO15rus [73]

Bruno had 10 bills for each if you don't count the 2 more $20 bills. If you want a complete number, bruno had 12 $20 dollar bills and 10 $10 bills

8 0

3 years ago

Bobby hopes that he will someday be more than 70 inches tall. He is currnebtyb70 inches tall how many more inches does bobby nee

xeze [42]

Bobby needs to grow at least 1 in to be more than 70 inches tall

8 0

3 years ago

The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What

Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that $\mu = 64.4, \sigma = 2.91$

Sample of 50 women

This means that $n = 50, s = \frac{2.91}{\sqrt{50}}$

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}$

$Z = 1.46$

$Z = 1.46$ has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0

2 years ago

Zahra compares two wireless data plans. Which equation gives the correct value of n, the number of GB, for which Plans A and B c

Elden [556K]

The equation which gives the correct value of n, the number of GB, for which Plans A and B cost the same is 8n = 20 + 6(n-2)

To determine which equation gives the correct value of n, the number of GB, for which Plans A and B cost the same, we will first solve the equations.

For the first equation

8n = 20 + 6n

Collect like terms

8n - 6n = 20

2n = 20

Then, n = 20 ÷ 2

n = 10 GB

For Plan A

No initial fee and $8 for each GB

Here, 10GB will cost 10 × $8 = $80

For Plan B

$20 for the first 2GB and $6 for each additional GB after the first 2

Here, 10GB will cost $20 + (8 × $6) = $20 + $48 = $68

∴ Plans A and B do not cost the same here.

For the second equation

8n = 20(2n) + 6

First, clear the bracket

8n = 40n + 6

Now, collect like terms

40n - 8n = 6

42n = 6

∴ n = 6 ÷ 42

n = 1/7 GB

For Plan A

No initial fee and $8 for each GB

Here, 1/7GB will cost 1/7 × $8 = $1.14

For Plan B

$20 for the first 2GB and $6 for each additional GB after the first 2

Here, 1/7GB will cost $20 (Since the lowest cost is $20)

∴ Plans A and B do not cost the same here.

For the third equation

8n = 20 + 6(n-2)

First, clear the brackets

8n = 20 + 6n - 12

Now, collect like terms

8n - 6n = 20 - 12

2n = 8

n = 8 ÷ 2

n = 4 GB

For Plan A

No initial fee and $8 for each GB

Here, 4GB will cost 4× $8 = $32

For Plan B

$20 for the first 2GB and $6 for each additional GB after the first 2

Here, 4GB will cost $20 + (2 × $6) = $20 + $12 = $32

Plans A and B do not cost the same here.

∴ Plans A and B do cost the same here

For the fourth equation

8n = 20 + 2n + 6

Collect like terms

8n - 2n = 20 + 6

6n = 26

n = $\frac{26}{6}$

n = $\frac{13}{3}$ GB or $4\frac{1}{3}$ GB

For Plan A

No initial fee and $8 for each GB

Here, $\frac{13}{3}$ GB will cost $\frac{13}{3}$ × $8 = $34.67

For Plan B

$20 for the first 2GB and $6 for each additional GB after the first 2

Here, $4\frac{1}{3}$ GB will cost $20 + ( $2\frac{1}{3}$ × $6) = $20 + $14 = $34

∴ Plans A and B do not cost the same here.

Hence, the equation which gives the correct value of n, the number of GB, for which Plans A and B cost the same is 8n = 20 + 6(n-2)

Learn more here: brainly.com/question/9371507

6 0

2 years ago