Answer: 7.15
Step-by-step explanation:
143
20
=7 and 3 over 207
3
20
=7.15
- 1.3 is the number we get when we subtract the sum of -5/6 and -1 3/5 from the sum of 2 2/3 and -6 2/5. This can be obtained by finding sum separately and then subtracting them.
<h3>What is the required number:</h3>
Here in the question it is given that,
subtract the sum of -5/6 and -1 3/5 from the sum of 2 2/3 and -6 2/5
By separating them as two parts
⇒ sum of -5/6 and -1 3/5
- 5/6 + - 1 3/5 = - 5/6 + - 8/5 (∵ a b/c = (ac+b)/c(5+3)/5 = 8/5)
= (- 25 - 48)/30 (LCM = 30)
= - 73/30
⇒ sum of 2 2/3 and -6 2/5
2 2/3 + -6 2/5 = 8/3 + -32/5
= (40 - 96)/15 (LCM = 15)
= - 56/15
subtract the sum of -5/6 and -1 3/5 from the sum of 2 2/3 and -6 2/5
= (sum of 2 2/3 and -6 2/5) - (sum of -5/6 and -1 3/5)
= (- 56/15) - (- 73/30 )
= - 56/15 + 73/30
= - 112/30 + 73/30 (LCM = 30)
= - 39/30
= - 13/10
= - 1.3
Hence - 1.3 is the number we get when we subtract the sum of -5/6 and -1 3/5 from the sum of 2 2/3 and -6 2/5.
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Answer:
The correct option is A.
Step-by-step explanation:
It is given that DEFG is a parallelogram.
Draw the diagonals DF and EG. Place point H where DF and EG intersect.
In triangle HGD and HEF
,
∠HGD ≅ ∠HEF (Alternate Interior angle)
∠HDG ≅ ∠HFE (Alternate Interior angle)
By the definition of a parallelogram, the opposite sides of a parallelogram are congruent.
DG ≅ EF (Opposite sides of parallelogram)
According to ASA postulate, two triangles are congruent if any two angles and their included side are equal in both triangles.
So, by using ASA criterion for congruence we get,
ΔDGH ≅ ΔFEH
Since corresponding sides of congruent triangles are congruent, therefore
GH ≅ EH (CPCTC)
DH ≅ FH (CPCTC)
Option A is correct.
It adds .8 for every 1 so it would be 6.2 and 7
