What is the equation of the line that passes through the point (-2,3) and that is perpendicular to the line represented by 3x-2y
= -2?
1 answer:
Answer:
3y + 2x = 5
Step-by-step explanation:
3x-2y = -2
2y = 3x + 2
y = (3/2)x + 1
Slope is 3/2
Slope of the Perpendicular line is -2/3
y = (-2/3)x + c
x = -2 , y = 3
3 = (-2/3)(-2) + c
3 = 4/3 + c
c = 3 - 4/3 = 5/3
y = (-2/3)x + 5/3
3y = -2x + 5
3y + 2x = 5
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Answer:
No solutions
Step-by-step explanation:
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-3x-y=-4 (by rewriting)
So
6/-3 = 2/-1≠20/-4
-2=-2≠-5
So it has no solutions
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Step-by-step explanation:
Answer:
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Explanation:
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Answer:
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Step-by-step explanation:
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