Add 2x and subtract 7
5 -2x +2x < 7 +2x . . . . . . showing 2x added
5 < 7 +2x . . . . . . . . . . . .. simplified
5 -7 < 7 -7 +2x . . . . . . . . showing 7 subtracted
-2 < 2x . . . . . . . . . . . . . . . simplified
Now, divide by 2
-1 < x
The solution is -1 < x.
673
x 86
------------
4038
+ 53840
------------
57878
Answer:
a. 50 students are randomly selected from the school; 11 drive to school
b. 407
Step-by-step explanation:
a. to get an accurate viewing, use random people that share 1 large common denominator (from the same school) that also has to do with the question
b. 11/50 is only between 50 students. make the denominator the same (1850) and multiply the same to the numerator
1850/50 = 37
11/50 x 37 = 407/1850
Answer:
45
Step-by-step explanation:
The different pairs of individual can be computed using rule of combination.
The combination is denotes as nCr.
nCr=n!/(r!(n-r)!)
In the given problem n=total candidates=10 and r= Selected candidates=2.
10C2=10!/(2!(10-2)!)
10C2=10*9*8!/(2!8!)
10C2=90/2
10C2=45
So, 45 different pairs of individuals can be selected.
If I'm understanding this correctly 20 rounded to the nearest ten would be 20