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Damm [24]
4 years ago
7

What is the quotient (x3 + 3x2 + 5x + 3) ÷ (x + 1)?

Mathematics
2 answers:
GalinKa [24]4 years ago
8 0

That would be x^2 + 2x + 3

Studentka2010 [4]4 years ago
7 0

Answer:

\frac{x^3+3x^2+5 x+3}{x+1}\\\\=\frac{x^3+x^2+2x^2+2x+3x+3}{x+1}\\\\=\frac{x^2\times(x+1)+2x\times (x+1)+3\times (x+1)}{x+1}\\\\=\frac{(x+1)(x^2+2x+3)}{x+1}\\\\=x^2+2x+3

⇒Quotient =x²+2 x+3

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ABC and DEF are similar. Find the missing side length.
mrs_skeptik [129]

Answer:

The missing side length is 5

Step-by-step explanation:

Basically 32 to 4 and 56 to 7 is 8 to 1, so you divide 40 by 8 to get the answer, 5

3 0
3 years ago
If a salesperson sells 3/4 of an acre for $80,000, what was the price per square foot rounded to two decimal spaces?
Julli [10]
Now, recalling that for 1 yard, there are 3 feet, therefore  \bf \begin{array}{ll}
yards&feet\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1yd&3ft\\
(1yd)^2&(3ft)^2\\
yd^2&3^2ft^2\\
&9ft^2
\end{array}

and keeping in mind that, there are 4840 yd² in 1 acre, then 

\bf \cfrac{\quad \frac{3}{4}~\underline{acre}\quad }{80000~\$}\cdot \cfrac{4840~\underline{yd^2}}{\underline{acre}}\cdot \cfrac{9~ft^2}{\underline{yd^2}}\implies \cfrac{\frac{3}{4}\cdot4840\cdot  9~ft^2}{80000~\$}\implies \cfrac{\frac{130680}{4}}{80000}
\\\\\\
\cfrac{\frac{130680}{4}}{\frac{80000}{1}}\implies \cfrac{130680}{4}\cdot \cfrac{1}{80000}\implies \cfrac{3267}{8000}~\frac{ft^2}{\$}~\approx~ 0.408375 ~\frac{ft^2}{\$}
5 0
4 years ago
solve x^2-8x=20 by completing the square. Which is the solution set of the equation? a {2, 10} b {-2, 10} c {2, -10} d {-2, -10}
torisob [31]

Answer:

B is the correct answer.

Step-by-step explanation:

7 0
3 years ago
The endpoints of EF<br> are E(1,3) and F(-2,8).<br> Find EF.
Phantasy [73]

Answer:

EF = \sqrt{34} ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = \sqrt{(-2-1)^2+(8-3)^2}

    = \sqrt{(-3)^2+5^2}

    = \sqrt{9+25}

    = \sqrt{34} ≈ 5.83 ( to 2 dec. places )

8 0
3 years ago
Help<br><br> Determine which equation is parallel to line jk and which is perpendicular to line jk.
alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes m_1 and m_2 are parallel when m_1=m_2 and are perpendicular when m_1*m_2=-1

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0
3 years ago
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