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3 years ago

Rewrite using a single positive exponent

Mathematics

1 answer:

Korolek [52]3 years ago

7 0

Answer:

9³

Step-by-step explanation:

We need to find the value of $\dfrac{9^5}{9^2}$ .

We know that,

$\dfrac{x^a}{x^b}=x^{a-b}$

Here, a = 5 and b = 2.

So,

$\dfrac{9^5}{9^2}=9^{5-2}\\\\=9^3$

So, the answer to the given expression is 9³.

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Which of the following represents 64 written with an exponent using base 4

adell [148]

Answer:

not enogugh information

Step-by-step explanation:

4 0

3 years ago

In the coordinate plane, the point X(-4, 0) is translated to the point X'(1, -3). Under the same translation, the points

topjm [15]

sorry i don't know the answer

6 0

3 years ago

Helppppppp<br> 3<br> Σ (2n – 3)<br> n=0

Nataly [62]

Since there are only 4 terms in the sum, it's not too much work to expand it as

$\displaystyle \sum_{n=0}^3 (2n-3) = -3 + (-1) + 1 + 3 = \boxed{0}$

Alternatively, we can use the well-known formulas

$\displaystyle \sum_{n=1}^N 1 = \underbrace{1 + 1 + \cdots + 1}_{N \text{ 1s}} = N$

$\displaystyle \sum_{n=1}^N n = 1+2+\cdots+N = \frac{N(N+1)}2$

These sums start at n = 0, so in our given sum we will keep track of the 0-th term separately:

$\displaystyle \sum_{n=0}^3 (2n-3) = -3 + \sum_{n=1}^3 (2n-3) = -3 + 2 \sum_{n=1}^3 n - 3 \sum_{n=1}^3 1 = -3 + 3\times4 - 3\times3 = 0$

as expected.

8 0

2 years ago

On a clear day you can see about 25.2 miles from the upper observation platform of the Eiffel tower in Paris. Using the formula

fredd [130]

Answer:

D. 914 feet

Step-by-step explanation:

We are given the distance that a person can see on a clear day from the upper observation platform of the Eiffel tower in Paris. We are then required to estimate the height of the upper observation platform using the formula;

$d=\frac{5}{6}\sqrt{h}$

Where d is the distance and h the height of the upper observation platform. The first step would be to solve for h, that is make h the subject of the formula in the above equation;

We multiply both sides of the equation by the reciprocal of 5/6 which is 6/5;

$\sqrt{h}=\frac{6}{5}d$