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Kay [80]
2 years ago
14

Rewrite using a single positive exponent

Mathematics
1 answer:
Korolek [52]2 years ago
7 0

Answer:

9³

Step-by-step explanation:

We need to find the value of \dfrac{9^5}{9^2}.

We know that,

\dfrac{x^a}{x^b}=x^{a-b}

Here, a = 5 and b = 2.

So,

\dfrac{9^5}{9^2}=9^{5-2}\\\\=9^3

So, the answer to the given expression is 9³.

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4(1/2x + 2) = 6
Goshia [24]
x=2. -5/6 have a great rest of your day
6 0
3 years ago
What is the quotient and the remainder for <br> 52 divided by 8
Marianna [84]
52/8 = 6 
6*8 = 48
52-48 = 4

So 52 = 6*8+4

The quotient is 6, the remainder is 4.
5 0
3 years ago
Convert 10300000in scientific notation​
insens350 [35]

Step-by-step explanation:

10300000 = 1,03 * 10⁷

3 0
3 years ago
Read 2 more answers
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
Find A ∩ B if A = {3, 6, 9, 12} and B = {2, 4, 6, 8, 10, 12}.
Helga [31]

Find A ∩ B is any numbers that are in both sets

they booth have 6 & 12 so the answer is: {6, 12}


6 0
3 years ago
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