A decrease of 8.25% means the reduction factor is 100-8.25=91.75%=0.9175.
The shrinkage over 15 years is 0.9175¹⁵=0.27485 approx, so the size of the forest will be 3100×0.27485=852 sq km approx.
Here is the factored polynomial
(x^2+9)(x^2-3x-9)=0
Answer:
Step-by-step explanation:
Let the length of each side of the cube be
x meters.
x3= 123,456
3 square root x3= 3 square root 123,456
x=49.8 m
The length of each side of the cube is
49.8 meters
Answer:
C.4.18g
The amount will remain after 12 days is 4.18 g
Step-by-step explanation:
we can use formula

where
h is half life time
t is time in days
Po is initial quantity
P(t) is the quantity after t days
we are given
Curium-243 has a half-life of 28.5 days

In a sample of 5.6 grams of curium-243
so,

now, we can plug values

now, we can plug t=12


So,
The amount will remain after 12 days is 4.18 g