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Allushta [10]
3 years ago
7

Anyone know? Help is much appreciated

Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer

ok

Step-by-step explanation:


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Spencer had a sack filled with pounds of cement. He removed some of the cement from the sack and put it into three buckets. He p
matrenka [14]

Answer:

...what's the question you want answered?

5 0
3 years ago
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Car Wash A theater group is having a carwash fundraiser. The liquid soap costs $34 and is enough to wash 40 cars. Each car is ch
mash [69]

a. If c is the total number of cars washed and p is the profit

The profit depends on the total number of cars washed.

So profit P is the dependent variable and C is the independent variable

(b) yes, the relationship between c and p a function

Because for each input for c, there will be an unique output for P

(c) C is the number of cars

Each car charged is $5

So C cars charged is 5C

The liquid soap costs $34 and is enough to wash 40 cars. So we subtract 34

Hence Profit P = 5c - 34

The equation is P = 5c - 34

(d) The liquid soap costs $34 and is enough to wash 40 cars

So number of cars is 0 to 40

0<=c <=40

soap costs $34

so profit is above 34

When cars = 40 then profit is 5(40) - 34= 166

So profit lies between 34  and 166

34<= P<= 166


5 0
3 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
3 years ago
Simplify: <br><br><br><br><br> ...............
Helga [31]
The answer can be shown in both exact and decimal forms.

Exact form:
\sqrt{61 - 24}\sqrt{5}

Decimal form:
2.70820393...

I hope this helps!
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful day! : )
5 0
4 years ago
Can someone please help me
Assoli18 [71]
To move it 1 to the left, we make x into (x+1), so we have (x+1)². Conversely, if we wanted to move it to the right, we'd subtract 1 from x. Next, we have to vertically stretch by a factor of 3, meaning that we have to multiply the whole thing (at the current point) by 3, turning our equation into 3(x+1)². Lastly, we must reflect over the x axis, which is the line g(x)=0. If we want to reflect over g(x), we essentially multiply g(x) by -1, making -g(x)=3(x+1)². However, we want to solve for g(x), not -g(x), so we multiply both sides by -1 to end up with -3(x+1)²
7 0
4 years ago
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