All categories

3 years ago

-1/2w-3/3=1/3w been struggling with the longest time. please help

Mathematics

1 answer:

algol133 years ago

7 0

Answer:

-6/5 = w

Step-by-step explanation:

-1/2w-3/3=1/3w

Add 1/2 w to each side

-1/2w+ 1/2 w -3/3=1/3w+ 1/2 w

-3/3 = 1/3w+ 1/2 w

-3/3 is 1

-1 = 1/3w+ 1/2 w

Get a common denominator for the right side of 6

-1 = 1/3*2/2 w + 1/2 *3/3 w

-1 = 2/6w + 3/6 w

-1 = 5/6 w

Multiply by 6/5 to isolate w

-1 *6/5 = 5/6*6/5 w

-6/5 = w

You might be interested in

Instructions:Simplify.Your answer should contain only positive exponents.

vagabundo [1.1K]

Answer:

11) -x to the power of 9/y to the power of 8

ᴍᴀᴛʜᴡᴀʏ can help you with the other problems.

Hope I could help!

5 0

3 years ago

What is the difference between perimeter and area of polygons?

madam [21]

Answer: The perimeter is when you add all of the sides together, and the area is when you multiply the sides together

Step-by-step explanation:

3 0

3 years ago

Pre-image ABCD was dilated to produce image A'B'C'D' What is the scale factor from the pre-image to the image?

Greeley [361]

Answer:

The answer is 3/4

Step-by-step explanation:

4 0

3 years ago

Phillip is rolling two number cubes. How many different ways can he roll the number cubes and get a sum of 6?

attashe74 [19]

Your answer you be A. 3

4 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=y%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20%20%3D%20%28x%5E2-%20%5Cfrac%7B1%7D%7B2%7D%20%29%5E2" id="T

zhenek [66]

Answer: $\bold{y=\dfrac{1\pm \sqrt{4x+13}}{2}}$

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y:

$y+\dfrac{13}{4}=\bigg(x-\dfrac{1}{2}\bigg)^2\\\\\\x+\dfrac{13}{4}=\bigg(y-\dfrac{1}{2}\bigg)^2\rightarrow \text{(swapped the x's and y's)}\\\\\\\sqrt{x+\dfrac{13}{4}}=\sqrt{\bigg(y-\dfrac{1}{2}\bigg)^2}\rightarrow \text{(took square root of both sides)}\\\\\\\sqrt{\dfrac{4x+13}{4}}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(created common denominator in radical)}\\\\\\ \dfrac{\sqrt{4x+13}}{2}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(simplified radical)}$

$\pm \dfrac{\sqrt{4x+13}}{2}=y-\dfrac{1}{2}}\rightarrow \text{(divided both sides by}\ \pm )\\\\\\\dfrac{1}{2}\pm \dfrac{\sqrt{4x+13}}{2}=y\quad \rightarrow \text{(added}\ \dfrac{1}{2}\ \text{to both sides)}\\\\\\\dfrac{1\pm \sqrt{4x+13}}{2}=y\quad \rightarrow \text{(combined numerators)}$

4 0

3 years ago