144.44 in² is the closest amount of paper she will use to wrap the gift.
Solution:
The given net is the shape of the cylinder.
Diameter of the circle = 4 in
Radius of the circle = 4 ÷ 2 = 2 in
Width of the container = 10.5 in
Length of the container is same as the circumference of the circle.
Area of the circle = 
= 
= 12.56 in²
Area of the 2 circles = 2 × 12.56 = 25.12 in²
Area of the rectangle = circumference × height
= 
= 
= 131.88 in²
Area of the net of the container
= Area of the circles + Area of the rectangle
= 12.56 in² + 131.88 in²
= 144.44 in²
Area of the net of the container = 144.44 in²
Hence 144.44 in² is the closest amount of paper she will use to wrap the gift.
X, X+2, and X+4 are the three odd integers.
2(X)+(X+4)=25 represents the problem.
2X+X+4=25
3X+4=25
3X=25-4
3X=21
X=7
Answer:
3+4p+8t
Step-by-step explanation:
Answer:
16.075 is the answer.
Step-by-step explanation:
16.075 is the answer. I hope this helps. You divide
64.3/7
=16.075
Answer:
30+4+0.7+0.05
Step-by-step explanation:
Because the expanded form is added the number.
3=30
4=4.
7=0.7
and 5=0.05 so all together is 30+4+0.7+0.05