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adelina 88 [10]
3 years ago
14

Solve this application problem using a system of equations: A grocery store recently sold a

Mathematics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

19 bags of peanuts and 31 bags of pistachios were sold.

Step-by-step explanation:

This question is solved by a system of equations.

I am going to say that:

x is the number of bags of peanuts sold.

y is the number of bags of pistachios sold.

50 bags of  peanuts and pistachios were sold

This means that x + y = 50, that is: x = 50 - y

A grocery store recently sold a  bag of peanuts for $0.76 and a bag of pistachios for $3.68. Were sold for a total of $128.52.

This means that:

0.76x + 3.68y = 128.52

Since x = 50 - y

0.76(50 - y) + 3.68y = 128.52

2.92y = 90.5

y = \frac{90.5}{2.92}

y = 31

x = 50 - y = 50 - 31 = 19

19 bags of peanuts and 31 bags of pistachios were sold.

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tiny-mole [99]

This is very similar to solving linear equations except for one thing, If we multiply or divide by a negative number, we must flip the inequality sign.

<h3>What is linear inequality?</h3>

In mathematics, inequality occurs when a non-equal comparison is made between two mathematical expressions or two numbers. In general, inequalities can be either numerical inequality or algebraic inequality or a combination of both.

To better understand it, let's examine the example.

2x - 5 < 3

So, when we solve, let's just consider the inequality sign like a regular equal sign.

Let's start by adding 5 to each sides.

2x - 5 + 5 < 3 + 5  

To find the value of x , we must divide  it by two.

2x/2 <8/2

And the final result is x= 4.

This is our answer.

So if we need to graph it, let’s draw a number line and draw an open circle at 4. Open circle because x is not equal to 4. Then make an arrow going to the left.

to know more about linear inequality and graph:

brainly.com/question/21103162

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5 0
1 year ago
A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week
Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals​ surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                              P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of individuals who work at home at least once per week = \frac{41}{250} = 0.164

           n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                             level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<em>99% confidence interval for p</em> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } , 0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } ]

 = [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

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Answer:

Area = 2m^8 - 6m^4 + 4.5

Step-by-step explanation:

Given

Base = 2m^4 - 3

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This is calculated as:

Area = 0.5 * Base * Height

Area = 0.5 * (2m^4 - 3) * (2m^4 - 3)

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