What is the answer in standard form for 314,207
1 answer:
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Answer:
The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Middle 90%
Between the 50 - (90/2) = 5th percentile to the 50 + (90/2) = 95th percentile.
5th percentile:
X when Z has a pvalue of 0.05. So X when Z = -1.645.
95th percentile:
X when Z has a pvalue of 0.95. So X when Z = 1.645.
The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758
Answer:
The 95% confidence interval for the population mean is between 17.93 days and 24.07 days.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 21 - 3.07 = 17.93 days
The upper end of the interval is the sample mean added to M. So it is 21 + 3.07 = 24.07 days
The 95% confidence interval for the population mean is between 17.93 days and 24.07 days.