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kow [346]
3 years ago
10

Jer saw 91 squirrels and 1⁄3 as many chipmunks. Which of the following is a good estimation of how many more squirrels he saw th

an chipmunks?180 more squirrels
30 more squirrels

87 more squirrels

53 more squirrels

60 more squirrels
Mathematics
1 answer:
boyakko [2]3 years ago
8 0
60 more squirrels is the answer because sine its an estimate, 91 turns into 90
therefore u have 
90 squirrels and 1/3 as many chipmunks
1/3 of 90 is 30
90 - 30 = 60
Your answer is 60 more squirrels

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Please help! I’ve always had trouble with these questions. It’d be a big hand.
deff fn [24]

2. c = 47,000 × n, where c is the cost of n number of bears.

3. a) The cost to ride 5 rides = $20.50, the cost to ride 8 rides = $28.00

The equation for the pattern, C(x) = 15.50 + 2.50 (r - 3), where C is the cost and r is the number of rides.

b) The cost to ride 12 rides = $36.00.

Step-by-step explanation:

Step 1; To find the cost of one bear, we divide the cost of bears by the number.

If 4 bears cost $188,000, 1 bear costs = \frac{188000}{4} = $47,000.

If 7 bears cost $329,000, 1 bear costs = \frac{329,000}{7} = $47,000.

So the equation is c = 47,000 × n, where c is the cost to buy n bears.

Step 2; For every additional ride, the price increases by $2.50. So the equation for the pattern is C(x) = 13.50 + 2.50 (x - 3).

When the number of rides is 5, C(5) = 15.50 + 2.50 (5-3) = 15.50 + 2.50 (2) = 15.50 + 5.0 = $20.50.

When the number of rides is 8, C(8) = 15.50 + 2.50 (8-3) = 15.50 + 2.50 (5) = 15.50 + 12.50 = $28.00.

When the number of rides is 12, C(12) = 15.50 + 2.50 (12-3) = 15.50 + 2.50 (9) = 13.50 + 22.5 = $36.00.

3 0
2 years ago
Help! Write two expression that have a sum of 3x-8
Nuetrik [128]

Answer:

(14 - x) + (4·x - 22) = 3·x - 8

6 0
3 years ago
Help me please ill give brainly
Andreas93 [3]

Answer:

y =  − 2 x  +  3

Step-by-step explanation:

Hope this Helps

5 0
3 years ago
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In the morning, a farm worker packed 3 pints of strawberries every 4 minutes. In the afternoon she packed 2 pints of strawberrie
Alex17521 [72]

Answer:

ones bigger than the other

Step-by-step explanation:

im bored & not being helpful sorry

5 0
2 years ago
Read 2 more answers
The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?
vekshin1
B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

Perimeter = 2(l + w)
Perimeter = 64

Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.


5 0
2 years ago
Read 2 more answers
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