Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.
<h3>What is the
area of the right-angle triangle?</h3>
The area of the right-angle triangle is given as
A = 1/2 x B x H
Where B is the base and H is the height of the right triangle.
We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.
α₁ = 40°
AO = OC = 7.8 cm
Then the area of the triangle will be
Area = 1/2 x 7.8 x 7.8 x tan40°
Area = 22.53 square cm
More about the area of the right-angle triangle link is given below.
brainly.com/question/16653962
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Formula for Perimeter of Rectangle:
P = 2(L + W)
Plug in 160:
160 = 2(L + W)
L = 4W
<span>So we can plug in '4W' for 'L' in the first equation.</span>
<span>160 = 2(L + W)
160 = 2(4W + W)
Combine like terms:
160 = 2(5W)
160 = 10W
Divide 10 to both sides:
W = 16
Now we can plug this back into any of the two equations to find the length.
L = 4W
L = 4(16)
L = 64
So the width is 16, and the length is 64.</span>
-7 - 8 - (-8) - 7 × 0(14) - 14 - 30
(I think that's what that says)
Do PEMDAS
0(14) = 0
-7 × 0 = 0
You're left with -7 - 8 - (-8) - 14 - 30
Go from left to right
-7 - 8 = -15
-15 - (-8) = -7
-7 - 14 = -21
-21 - 30 = -51
Answer:
m = - 15
Step-by-step explanation:
Using the rule of exponents
× 
= 
, then
× 
= 
, that is
=
=
Equating exponents gives
m = - 15
Answer:
explanation:
put x values in the function in order to find y values.
<u> ___x___ ___y___ </u>
0 | -5
1 | -4.2
2 | -3.4
3 | -2.6
4 | -1.8
5 | -1
6 | -0.2
