Answer:
Mass of CO₂ = 3.08 g
Explanation:
Given data:
Mass of organic fuel = 2.63 g
Molar mass of organic fuel = 74.09 g/mol
Mass of oxygen = 5.63 g
Mass of carbon dioxide = ?
Solution:
Chemical equation:
2C₃H₆O₂ + 7O₂ → 6CO₂ + 6H₂O
Number of moles of organic fuel:
Number of moles = mass / molar mass
Number of moles = 2.63 g / 74.09 g/mol
Number of moles = 0.035 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles =5.63 g / 32 g/mol
Number of moles = 0.176 mol
Now we will compare the moles of O₂ and C₃H₆O₂ with CO .
C₃H₆O₂ : CO
3 : 6
0.035 : 6/3 × 0.035 = 0.07
O₂ : CO
7 : 6
0.176 : 6/7 × 0.176 = 0.151 mol
The number of moles of CO₂ produced by C₃H₆O₂ are less it will be limiting reactant.
Mass of carbondioxide:
Mass of CO₂ = moles × molar mass
Mass of CO₂ = 0.07 mol × 44 g/mol
Mass of CO₂ = 3.08 g
