Answer: -
1595 g
Explanation: -
Heat of vaporization = 2.4 Kj/ g
Mass of water to be vaporized = 50 g
Heat released = Mass of water to be vaporized x Heat of vaporization
= 50 g x 2.4 KJ /g
= 120 KJ
= 120000 J
Initial temperature= 33+273= 306 K
Final temperature =15+273=288 K
Change in temperature required = T = 306 - 288 = 18 K
specific heat of water is 4.18 J / g K
Mass of water that can be cooled = Total heat / (specific heat of water x Change in temperature)
= 120000 J / ( 4.18 J / g K x 18 K)
= 1595 g
Insulator! I hope this helps! Pls mark mine the brainliest;)
Answer:
9.8×10^-4...... is the answer
B is the correct answer to your question
