Find the difference per row:
10 seats in the first row
30 seats in the sixth row:
30 -10 = 20 seats difference.
6-1 = 5 rows difference.
20 seats / 5 rows = 4 seats per row.
This means for every additional row, there are 4 more seats per row.
The equation would be:
Sn = S +(n-1)*d
Where d is the difference = 4
S = number of seats from starting row = 10
n = the number of rows wanted
S(11) = 10 + (11-1)*4
S(11) = 10 + 10*4
S(11) = 10 + 40
S(11) = 50
Check:
Row 6 = 30 seats
Row 7 = 30 + 4 = 34 seats
Row 8 = 34 + 4 = 38 seats
Row 9 = 38 + 4 = 42 seats
Row 10 = 42 + 4 = 46 seats
Row 11 = 46 + 4 = 50 seats.
Answer:
Again, I already answered this in a thorough manner in a past post...look in your notifications.
Have a great day!
The option (B) 2,-2 is correct because the number satisfy the provided expression.
<h3>What is an arithmetic operation?</h3>
It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
We have a number bank shown in the picture.
The problem given:
7 - __ = 7 + __
A. 3,-4
Checking for the above option:
7 - 3 = 7 - 4
4 = 3 (false)
B. 2,-2
Checking for the above option:
7 - 2 = 7 - 2
5 = 5 (true)
O C. 1;-4
Checking for the above option:
7 - 1 = 7 - 4
6 = 3 (false)
D. 2; 3
Checking for the above option:
7 - 2 = 7 + 3
5 = 10 (false)
Thus, the option (B) 2,-2 is correct because the number satisfy the provided expression.
Learn more about the arithmetic operation here:
brainly.com/question/20595275
#SPJ1
Answer:
My I don't know it is stupied!
Step-by-step explanation:
Answer:
(a) median = 57
(b) Q1=50 Q3=63.5
(c)D1 = 41 D9=67
(d)P33= 51
Step-by-step explanation:
(a) The numbers are arranged in ascending order, and there are even number of calls. So the median will be the average of the middle terms.
middle terms are 55 and 59
Median = 
median= 57
(b) First quarter Q1 = 
th
=
th
= 7.5th
so the first quarter lies in the 7.5th= (7+0.5)th term
So we multiply 0.5 by the difference of the 7th and 8th term
=0.5 *0= 0
Q1 = 50+0=50
Q3=
th
=
th
=22.5th = (22+0.5)th term
So we multiply 0.5 by the difference of the 22th and 23rd term
= 0.5*1=0.5
Q3= 63+0.5=63.5
(c) First decile (D1) = 
th
=
th
= 3rd term
D1= 41
D9= 
th
=
th
=27th term
D9 = 67
(d) 33rd percentile =
th
=
th
= 9.9th term = (9 +0.9)th
Multiply 0.9 by the difference between the 9th and tenth term.
= 0.9*0 =0
P33 = 51
