Answer:
650
Step-by-step explanation:
195
_. of 30
100
and these 30 zero cut and 100 zero also cut and 3 * 195= 65 and 65 x 10 =650
This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.
Each AP class counts twice and counts as 2 classes.
Class Ben's grade Points Number of Classes
AP English B 3 + 3 2
AP Government B 3 + 3 2
AP Algebra II A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8
GPA = (total points)/(number of classes) = 24/8 = 3
<span>Answer: B 3.0</span>
Answer: 8x
Step-by-step explanation:
Product stands for multiplication, so we need to use (×)
Let x = the number.
----------------------------------------------
The product of 8 and a number
8 × x=8x
Answer:
Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_a%5Eb%5BR%28x%29%5E2-r%28x%29%5E2%5Ddx)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is
there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have
and by replacing in the integral we have
![V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_%7Bx1%7D%5E%7Bx2%7D%5B%28lnx%2B5%29%5E2-%28%5Cfrac%7B1%7D%7B2%7Dx%2B3%29%5E2%5Ddx%5C%5C)
![V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5B28x%2B%5Cfrac%7B1%7D%7Bx%7D%2Bxln%5E2x-12xlnx-6lnx%5D)
and by evaluating in the limits we have
Hope this helps
regards
12 problems = 30 minutes
24 problems = 60 minutes
36 problems= 90 minutes
48 problems = 120 minutes
60 problems = 150 minutes
Mary can respond 60 problems in 2 hours and 30 minutes/ 2 hours and half/ 150 minutes.
Hope this helps xx
