Question

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviation for the number of hours students practiced the violin? Round to the nearest tenth.
6.4
6.8
32
47

Answer 1

Answer:

Mean  absolute deviation = 6.4

Step-by-step explanation:

Given : Data  45, 38, 52, 58, and 42 hours.

To find : What is the mean absolute deviation for the number of hours students practiced the violin? Round to the nearest tenth.

Solution : We have given that

45, 38, 52, 58, 42

Mean Deviation = Σ|x − μ|/N.

Where, x =  given values like 45,38...etc

           μ = mean .

       N  = total number of values .

We need to find mean = $\frac{45+38+52+58+42}{5}$

   Mean (  μ ) = 47.

|x − μ| = |45 − 47| = 2

|38− 47| = 9

|52− 47| = 5

|58− 47| = 11

|42− 47| = 5

Then Mean Deviation = $\frac{2+9+5+11+5}{5}$

Mean  absolute deviation = 6.4

Therefore ,Mean  absolute deviation = 6.4

Answer 2

Your answer should be 6.4 if you attempt to solve this. I hope this helps your question!