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Effectus [21]
3 years ago
12

A decimal in which a schedule or is a sequence of digits keeps repeating

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0
The answer would be a repeating decimal 
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Which situation explains how a credit becomes a debt?
mylen [45]
The answer is A because its the only answer that explains the process of credit becoming debt correctly.
5 0
2 years ago
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The sum of two numbers is 73. Twice the smaller number is one less than the larger number. The smaller number is
Ilya [14]

Answer:

The big number is 41 and the small number is 32.

Step-by-step explanation:

b + s = 73

2b - s = 50        Add these equations together

3b = 123            Divide both sides by 3

b = 41

Now plug this into the first equation to find s

41 + s = 73

-41       - 41

s = 32

6 0
3 years ago
Factor:<img src="https://tex.z-dn.net/?f=27x%5E3%2B8" id="TexFormula1" title="27x^3+8" alt="27x^3+8" align="absmiddle" class="la
irinina [24]

Answer:

(3x + 2)(9x^2 - 6x + 4)

Step-by-step explanation:

Simple Question.

27x^3 + 8 = (3x)^3 + (2)^3

You can now apply the sum of the cubes formula:

x^3 + y^3 = (x + y)(x^2 - xy + y^2),

(3x)^3 + (2)^3 = (3x + 2)(3^2x^2 - 2*3x + 2^2)

                      =  (3x + 2)(9x^2 - 6x + 4)

Solution: (3x + 2)(9x^2 - 6x + 4)

6 0
2 years ago
Use the number line to help you decide which statement is true.<br> (A)<br> (B)<br> (C)
pshichka [43]

Answer:

I think it's (A). 5

I don't know

3 0
3 years ago
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K<br> dubnppppppdwadadaaaaaaaaaaaa
MaRussiya [10]

<em>If he draws at random there is a </em><u><em>3/7 percent chance that he will pull an odd number </em></u><em> Here's why :</em>

<em />

  • There are seven numbers making the denominating factor 7 and out of those 7 factors only 3 of them are odd numbers
  • Making the nominating factor 3 so it should look like this
  • 3/7 because three off the seven numbers are odd
  • so therefore there is a 3/7 percent chance at pulling an odd number.
4 0
3 years ago
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