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3 years ago

A decimal in which a schedule or is a sequence of digits keeps repeating

Mathematics

1 answer:

Vitek1552 [10]3 years ago

8 0

The answer would be a repeating decimal

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I need help does anyone know?

Nuetrik [128]

Answer:

$19.6

Step-by-step explanation:

He bought 6 video games and 1 dvd

We know that each video game costs $2.7 and each dvd costs 3.4

To get the sum = v x 6 + d x 1

= 2.7 x 6 + 3.4 x 1

= 16.2 + 3.4

= $19.6

4 0

3 years ago

What plus 35 equals 180

Katarina [22]

145. u take 180 subtract 35. It will gives u 145

4 0

3 years ago

Read 2 more answers

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago

Write the following number in standard form. three and fifteen hundredths 3.15 3.015 315 3.105

soldier1979 [14.2K]

3.105 I believe.. not 100% sure.

3 0

3 years ago

(-4)(5)+(-3)(-2) whats is it???

Vlada [557]

Answer:

-14

Step-by-step explanation:

(-4)(5)+(-3)(-2)

=-20+6

=-14

5 0

4 years ago

Read 2 more answers