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Makovka662 [10]
3 years ago
5

How many solutions does the equation 4s + 8 = 3 + 5 + 4s have?

Mathematics
2 answers:
cluponka [151]3 years ago
5 0

Answer:

The answer is none.

Step-by-step explanation:

MAXImum [283]3 years ago
3 0

Answer:

none

Step-by-step explanation:

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Sasha has 3.20 in U.S. coins. She has the same number of quarters and nickels. What is the greatest number of quarters she could
RSB [31]

Answer:

10 quarters = $2.50

10 nickels = $0.50

that leaves $0.20 for other coins (dimes / pennies)

Step-by-step explanation:

First, suppose she has only quarters and nickels and no other coins.  Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this.  So she must have at least one other type of coin.

Assume she has only quarters, nickels, and dimes.  Then if D is the number of dimes, 5C +  25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32.  The smallest D can be is 2, leaving 3C = 30 and thus C = 10.  So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.

This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.

8 0
3 years ago
Read 2 more answers
Find the point on the graph of y=x^2 where the tangent line has slope m= - 1/3
babunello [35]

Here the graph y=x²

Taking the 1st derivative here of the y it will be

y1 = 2x

m=-1/3

That is m=2x

so x=-1/6

so y=(-1/6)²=1/36

So the coordinate of point will be=(-1/6 , 1/36)

8 0
4 years ago
Find the function of which is the solution of 36y"-48y'-48y=0 with initial conditions y1(0)=1. y1'(0)=0
lilavasa [31]

Answer:

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

Step-by-step explanation:

Let,  D=\frac{d}{dx}

Now, us simplify the given differential equation and write it in terms of D,

36y''-48y'-48y=0

or, 3y''-4y'-4y=0

or, (3D^2-4D-4)y=0

We have our auxiliary equation:

3D^2-4D-4=0

or, (3D+2)(D-2)=0

or, D=2, - \frac{2}{3}

Therefore our solution is,

y=Ae^{2x}+Be^{- \frac{2}{3}x}

and, y'=2Ae^{2x}-\frac{2}{3}Be^{\frac{2}{3}x }

Applying the boundary conditions, we get,

A+B=1

2A-\frac{2}{3}B=0

Solving them gives us,

A=\frac{1}{4} ,B=\frac{3}{4}

Hence,

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

4 0
3 years ago
What is the product of (1.9*10^-3)(2*10^4)
RoseWind [281]

Answer:

to solve use the distributive property and multiply

Step-by-step explanation:

I'm sorry I do not have the product

4 0
3 years ago
Read 2 more answers
Please help and answer the question properly.
RUDIKE [14]

Answer:

x = 15.65 and y = 5√2

Step-by-step explanation:

To get x and y we will use the Pythagoras theorem as shown

hyp^2 = adj^2 + opp^2

x^2 = 14^2+7^2

x^2 = 196 + 49

x^2 = 245

x = √245

x = 15.65

Similarly for y;

y2 = 5^2 + 5^2

y^2 = 25 + 25

y^2 = 50

y = √2*25

y = 5√2

Hence x = 15.65 and y = 5√2

6 0
3 years ago
Read 2 more answers
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