2x-5<3x+6 ahah help!!!!!!

Find values of x and y for which ABCD must be a parallelogram. The diagram is not drawn to scale.

Arturiano [62]

ANSWER
$x=4, y=8$

EXPLANATION

If ABCD is a parallelogram, then

line AB is parallel to line DC .

This means that,

$(x + 2) \degree$
and

$(2x - 2) \degree$
are alternating angles.

Alternate angles are congruent.

This implies that,

$2x - 2 = x + 2$

We group like terms to obtain,

$2x - x = 2 + 2$

This simplifies to,

$x = 4$

Also, if ABCD is a parallelogram then,

BC is parallel to AD. This means that,

$5y - 8 = y + 24$

We group like terms to get,

$5y - y = 24 + 8$

This simplifies to,

$4y = 32$

We divide both side by 4 to get,

$y = 8$

6 0

3 years ago

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Tessa spent $22 on 11 song downloads. How much did each song cost?

Reika [66]

Answer:

Each song cost $2

Step-by-step explanation:

2 times 11 is 22

Make me brainliest if this helps!

4 0

3 years ago

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Andrea enjoys running. She keeps a daily journal to record how far she runs. She wears a pedometer to calculate the exact distan

Lana71 [14]

Again this is a simple addition problem I think.

Add 3.6+4.705+5.92=

14.225 kilometers that Andrea ran over the three days.

Hope this helps, have a good day. c;

5 0

3 years ago

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The equations in this sytem were added to solve for x. What is the value of x?

son4ous [18]

Question:

The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3

Options:

x = negative 3

x = negative 1

x = 1

x = 3

Answer:

The value of x is 1

Solution:

Given system of equations are:

-2x + y = 8 ------- eqn 1

5x - y = -5 ------- eqn 2

The above equations are added to solve for "x"

Add eqn 1 and eqn 2

-2x + y + 5x - y = 8 - 5

Combine the like terms

-2x + 5x + y - y = 3

Add the like terms

3x + 0 = 3

3x = 3

Divide both sides of equation by 3

x = 1

Thus the value of x is 1

8 0

3 years ago

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The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6

Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

Given the data in the question;

Constant Volume of a rectangular box with a square base = 500 cm³

area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0

⇒ dh/dt = -hdA/dt / A

we substitute

dh/dt = [ -( 500 / 225 ) × 6 ] / 225

dh/dt = [ -(2.22222 × 6) ] / 225

dh/dt = [ -13.3333 ] / 225

dh/dt = -0.0593 cm/s

Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s

7 0

3 years ago