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Keith_Richards [23]
2 years ago
8

4x + 2 < 2x + 9 Which graph shows the solution of the inequality?

Mathematics
1 answer:
Savatey [412]2 years ago
7 0

Answer:

i am pretty sure it's B correct me if i am wrong

Step-by-step explanation:

You might be interested in
If<br> 21 = 42<br> 39 = 618<br> 17 = 214<br> then what does<br> 45 = ?
Brums [2.3K]

Answer:

810

Step-by-step explanation:

21 = 42

Decode:

Number in the tens place = 2 x 2 = 4

Number in the ones place = 1 x 2 = 2

Answer: 42

39 = 618

Decode:

Number in the tens place = 3 x 2 = 6

Number in the ones place = 9 x 2 = 18

Answer: 618

17 = 214

Decode:

Number in the tens place = 1 x 2 = 2

Number in the ones place = 7 x 2 = 14

Answer: 214

Find 45

Number in the tens place = 4 x 2 = 8

Number in the ones place = 5 x 2 = 10

Answer: 810

3 0
2 years ago
Tia measured a greeting card and found that it was 1 decimeter long. How many centimeters are in 1 decimeter?
Advocard [28]

Answer:

10 cm

Step-by-step explanation:

1 decimeter is equal to 10⁻¹ meters.

1 meter is equal to 10² centimeters. We can use a conversion fraction to find the centimeters corresponding to 10⁻¹ meters.

10⁻¹ m × (10²cm/1 m) = 10 cm

1 dm = 10⁻¹ m

10⁻¹ m = 10 cm

Due to the transitive property, 1 decimeter is equal to 10 centimeters.

4 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!!!
Nookie1986 [14]
Plug in 6 for x and solve out for f(x)
8 0
3 years ago
8/20 greater than or less than 2/10
kumpel [21]
8/20 is greater than 2/10. If you were to make the denominators the same, by mulipling 2x2 and 10x2, you would get 4/20, which is less than 8/20.
6 0
3 years ago
Read 2 more answers
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
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