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mr Goodwill [35]
3 years ago
6

While out on a hike, you find an unknown mineral. How would you test the mineral to find out what it is?

Chemistry
1 answer:
notsponge [240]3 years ago
6 0
Are there answer choices or is it just right it your self?
You might be interested in
When writing the chemical formulas for a molecular compound, what method do you use?​
podryga [215]

Answer:

A molecular compound is usually composed of two or more nonmetal elements. Molecular compounds are named with the first element first and then the second element by using the stem of the element name plus the suffix -ide.

4 0
3 years ago
A solid with a density of 3.57g/mL and mass of 19.5g is added to a graduated cylinder that contain 23.2mL of water. What is the
NNADVOKAT [17]

Answer:

Volume of liquid = 28.7 mL

Explanation:

Given data;

Density of solid = 3.57 g/ml

Mass of solid = 19.5 g

Volume of water = 23.2 mL

Total volume when solid is dropped into graduated cylinder= ?

Solution:

Density = mass/ volume

v = m/d

v = 19.5 g/ 3.57 g/ml

v = 5.5 mL

Volume of liquid = volume of water + volume of solid

Volume of liquid = 23.2 mL + 5.5 mL

Volume of liquid = 28.7 mL

3 0
3 years ago
What is the pH of a neutral solution at 25°C?<br> 7<br> 1
Kaylis [27]

Answer:

I pretty sure it's the pH level 7

8 0
3 years ago
Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the tra
Anna007 [38]

Answer:

Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:

Electron density during transition

As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.

Explanation:

4 0
2 years ago
Calculate the moles of argon gas at STP in 33 L. Round answer to 2 significant figures.
babymother [125]

Answer:

1.5 mol

Explanation:

Step 1: Given data

  • Volume of argon gas: 33 L
  • Standard temperature: 273.15 K
  • Standard pressure: 1 atm

Step 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)

At STP, 1 mole of argon gas occupies 22.4 L.

33 L × 1 mol/22.4 L = 1.5 mol

4 0
3 years ago
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