<u>Answer:</u>
16.8 cups
<u>Explanation:</u>
We are given that there are 4.2 cups in in 1 liter of a liquid and we are to find out the number of cups that there will be in 4 liters.
To find this out, we will use the ratio method.
We know that:
1 L = 4.2 cups
So we can write it as:
Therefore, there are 16.8 cups in 4 liters.
Crushed sugar because it can’t take up as much height space
Answer:
3.44 × 10²⁴ atoms of oxygen
Explanation:
Step 1: Calculate the moles corresponding to 163 g of Al₂(SO₄)₃
The molar mass of Al₂(SO₄)₃ is 342.15 g/mol.
163 g × 1 mol/342.15 g = 0.476 mol
Step 2: Calculate the molecules in 0.476 moles of Al₂(SO₄)₃
We will use Avogadro's number: there are 6.02 × 10²³ molecules of Al₂(SO₄)₃ in 1 mole of Al₂(SO₄)₃.
0.476 mol × 6.02 × 10²³ molecules/1 mol = 2.87 × 10²³ molecules
Step 3: Calculate the atoms of O in 2.87 × 10²³ molecules of Al₂(SO₄)₃
According to the chemical equation, the molar ratio of Al₂(SO₄)₃ to O is 1:12. The atoms of O are 12/1 × 2.87 × 10²³ = 3.44 × 10²⁴.
Answer:
139.11 grams
Explanation:
The molarity (M) is equal to m (moles) /L (liters).
Notice how it is in mL so converting it would be 0.75 L (750*10-3)
Now plug in the information
1.75=m/0.75
m=1.3125
Now m is in moles so convert to grams to get the mass
1.3125 mol Na2CO3 * 105.9888 g Na2CO3 = 139.1103
Answer:
New volume = 
L
Explanation:
Using Charle's law
Given ,
V₁ = 
L
V₂ = ?
T₁ = 11 °C
T₂ = 105 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (11 + 273.15) K = 284.15 K
T₂ = (105 + 273.15) K = 378.15 K
Using above equation as:
<u>New volume = L</u>
