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3 years ago

How many grams of fe2o3 are present in 0.82 mol?

Chemistry

2 answers:

muminat3 years ago

6 0

Answer:- There are 131 g of $Fe_2O_3$ in 0.82 moles of it.

Solution:- It is a mol to gram conversion. We have been given with 0.82 moles of $Fe_2O_3$ and asked to convert it to grams.

For mol to gram conversion we multiply the moles by the molar mass.

Atomic mass of Fe is 55.85 and atomic mass of O is 16. So, molar mass of $Fe_2O_3$ = 2(55.85) + 3(16)

= 111.7 + 48

= $159.7(\frac{g}{mol})$

Let's convert the moles to grams as:

$0.82mol(\frac{159.7g}{mol})$

= 131 g

So, there are 131 g of $Fe_2O_3$ present in 0.82 mol of it.

mars1129 [50]3 years ago

5 0

130.954g of Fe2O3 in 0.82 mol

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