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vaieri [72.5K]
2 years ago
12

How many grams of fe2o3 are present in 0.82 mol?

Chemistry
2 answers:
muminat2 years ago
6 0

Answer:- There are 131 g of Fe_2O_3 in 0.82 moles of it.

Solution:- It is a mol to gram conversion. We have been given with 0.82 moles of Fe_2O_3 and asked to convert it to grams.

For mol to gram conversion we multiply the moles by the molar mass.

Atomic mass of Fe is 55.85 and atomic mass of O is 16. So, molar mass of Fe_2O_3 = 2(55.85) + 3(16)

= 111.7 + 48

= 159.7(\frac{g}{mol})

Let's convert the moles to grams as:

0.82mol(\frac{159.7g}{mol})

= 131 g

So, there are 131 g of Fe_2O_3 present in 0.82 mol of it.


mars1129 [50]2 years ago
5 0
130.954g of Fe2O3 in 0.82 mol
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