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3 years ago

(LCD) of 7 and 10 6

Mathematics

2 answers:

denpristay [2]3 years ago

7 0

Your given question is unclear.

o-na [289]3 years ago

7 0

The LCD of 7 and 10 is 1 , The LCD of 7 and 106 is 1 I was unclear what your question was but I tried:)

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A cross section is the intersection of a (solid or point) and a(plane or line) .

Rina8888 [55]

Answer:

A cross section is the intersection of a solid and a plane.

Step-by-step explanation:

A cross section is the geometric place formed when an 3-D object (solid) is cut straight.

Imagine the shape that you can see when you cut a piece of cheese with a knife. If the piece of cheese is a cube, the resultant shape, the cross section, will be a square.

Also, you can imagine the shape formed when you cut a right cylinder (the solid) with a plane parallel to the base. In this case, the cross section will be a circle.

Depending on the form of the solid and the angle of the plane, different cross sections may be obtained.

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3 years ago

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A pair of vertical angles has measures (2y + 5) and (4y) What is the value of y?

iogann1982 [59]

Answer:

Vertical angles are angles that are opposite each other when two lines intersect each other. And they are always equal.

==> 2y +5 = 4y

==> 4y - 2y = 5

==> 2y = 5

==> $y = \frac{5}{2}$

Option D

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3 years ago

What equation models the data in the table if d = numb of days and c = cost?

anyanavicka [17]

Answer:

c=3d

Step-by-step explanation:

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3 years ago

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Law Incorporation [45]

Answer:

Step-by-step explanation:

To solve this problem, we will use the following two theorems/definitions:

- Given a vector field F of the form (P(x,y,z),Q(x,y,z),W(x,y,z)) then the divergence of F denoted by $\nabla \cdot F = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}}+\frac{\partial W}{\partial z}$

- (Gauss' theorem)Given a closed surface S, the following applies

$\int_{S} F\cdot \vec{n} dS = \int_{V} \nabla \cdot F dV$

where n is the normal vector pointing outward of the surface and V is the volume bounded by the surface S.

Let us, in our case, calculate the divergence of the given field. We have that

$\nabla \cdot F = \frac{\partial}{\partial x}(x)+\frac{\partial}{\partial y}(2y)+ \frac{\partial}{\partial z}(5z) = 1+2+5 = 8$

Hence, by the Gauss theorem we have that

$\int_{S} F\cdot \vec{n} dS = \int_{V} 8 dV = 8\cdot\text{Volume of V}$

So, we must calculate the volume V bounded by the cube S.

We know that the vertices are located on the given points. We must determine the lenght of the side of the cube. To do so, we will take two vertices that are on the some side and whose coordinates differ in only one coordinate. Then, we will calculate the distance between the vertices and that is the lenght of the side.

Take the vertices (1,1,1) and (1,1-1). The distance between them is given by

$\sqrt[]{(1-1)^2+(1-1)^2+(1-(-1)^2} = \sqrt[]{4} = 2$ .