Answer:
Company one charges $11 + $0.16 per min.
Then if you talk for x minutes, the cost will be:
C₁(x) = $11 + ($0.16 per min)*x
For company two, the prize is $20 + $0.11 per min, and if yo talk for x minutes, the cost will be:
C₂(x) = $20 + ($0.11 per min)*x
Now we want to find the value of x, the number of minutes, such that the cost is the same with both companies.
C₁(x) = C₂(x)
$11 + ($0.16 per min)*x = $20 + ($0.11 per min)*x
($0.16 per min)*x - ($0.11 per min)*x = $20 - $11
($0.05 per min)*x = $9
x = $9/($0.05 per min) = 180 mins
If you speak for 180 minutes, the cost is the same in both companies.
Given:
Original or base : 40
New amount : 72
We need to find the difference of the new amount and the original amount
72 - 40 = 32
We then divide the difference by the original amount
32/40 = 0.80
We multiply the quotient by 100%
0.80 x 100% = 80%
The percentage of change is 80%
Step-by-step explanation:
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Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
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<u />
<u />
<u>Step 2: Evaluate</u>
- [Fraction] Exponents:
- [Fraction] Subtract:
- [Fraction] Divide:
c. t = 18h
is the appropriate expression for t equals 18 times h.
