Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k
parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t
Step-by-step explanation: The vector equation is a line of the form:
r = 
+ t.v
where
is the position vector;
v is the vector;
For point (7,4,5):
= 7i + 4j + 5k
Then, the equation is:
r = 7i + 4j + 5k + t(3i + 2j - k)
<u><em>r = (7 + 3t)</em></u><u><em>i</em></u><u><em> + (4 + 2t)</em></u><u><em>j </em></u><u><em>+ (5 - 5t)</em></u><u><em>k</em></u>
The parametric equations of the line are of the form:
x = 
+ at
y = 
+ bt
z = 
+ ct
So, the parametric equations are:
<em><u>x = 7 + 3t</u></em>
<em><u>y = 4 + 2t</u></em>
<em><u>z = 5 - 5t</u></em>
9 hundreds 4 ten thousends 8 ones 7 tens = 940008,7
hope helped
Answer:
i think that the answer is 5°
Answer:
<h3>cosθ = c/√1+c²</h3>
Step-by-step explanation:
Given cot θ = c and 0 < θ < π/2
In trigonometry identity:
cotθ = 1/tanθ = c
1/tanθ = c
cross multiply
tanθ = 1/c
According to SOH, CAH, TOA:
Tanθ = opposite/adjacent = 1/c
cosθ = adjacent/hypotenuse
To get the hypotenuse, we will use the pythagoras theorem:
hyp² = opp²+adj²
hyp² = 1²+c²
hyp = √1+c²
Find cosθ in terms of c
cosθ = c/√1+c²
Hence the formula for cos θ in terms of c is cosθ = c/√1+c²
Answer:
opposite sides with equal length
hope it helps
