Answer:
y = (-6/13)x + (4/13).,
Step-by-step explanation:
the equation of the line is:
y = mx + b, where "m" is the slope and "b" gives the y-intercept
m = (y2 - y1)/(x2 - x1)
m = (-2 - 4)/(5 - (-8))
m = -6/13
y = (-6/13)x + b
the line passes through the point (-8,4) means that for x = -8, y = 4
4 = (-6/13)(-8) + b
b = 4 - (-6/13)(-8)
b = 4/13
the equation of the line that passes through the points (-8,4) and (5,-2) is:
y = (-6/13)x + (4/13).
Y= f(x)= ax+b
when x= -1, y= -1
-1= -a+b | * ( -1)
when x= -3, y=2
2= -3a+b
-3a+b= 2
a - b= 1
--------------
2a=3
a=3/2 is the slope
Slope intercepf is y=mx+b wherem=slope and b= y intercept
slope is found by doing
(y1-y2)/(x1-x2)
points are (6,-1) and (-3,2)
(x,y)
x1=6
y1=-1
x2=-3
y2=2
subsitute
(-1-2)/(6-(-2))=-3/(6+2)=-3/8
slope=-3/8
subsitute
y=-3/8x+b
subsitute and solve for b
(-3,2)
x=-3
y=2
2=-3/8(-3)+b
2=9/8+b
2=16/8
subtract 9/8 from both sides
16/8-9/8=b
7/8=b
y=-3/9x+7/8 is the equation
