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postnew [5]
3 years ago
14

The length of a rectangle is 4 inches more than its widith. The area of the rectangle is equal to 4 inches less than 3 times the

perimeter. Find the length and width of rectangle
Mathematics
1 answer:
zepelin [54]3 years ago
6 0
Length is 14
width is 10
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frosted honey krunch cereal comes in a box that is 8.5 wide , 11.4 high and 2.6in deep what is the volume of the box ?
Butoxors [25]

Answer:

2519.4in³

Step-by-step explanation:

Volume=l×h×w

=8.5×11.4×2.6

2519.4

hope this helps

please like and Mark as brainliest

8 0
3 years ago
Read 2 more answers
Help please I don’t understand this at all & been stuck here for a hour
ELEN [110]

Answer:

Step-by-step explanation:

4b + 8 = 20

Subtract 8 from both sides

4b + 8 - 8 = 20 - 8

4b = 12

Now divide both sides by 4

4b/4 = 12/4

b = 3

Check:

LHS = 4b + 8

       = 4*3 + 8

        = 12 + 8

        = 20 = RHS

4 0
3 years ago
[20 POINTS]
DiKsa [7]

If all you want is a horizontal shrink then the answer you choose should not be in brackets. The brackets will alter the way the graph looks.


That means that A and B are not correct.


If you have a graph where a>1 the graph will expand.

If you have a graph where a<1 but greater than 0 the graph will shrink.


y = 1/2 x^3 + 4 is the answer you want.


Just to show you the graphs, I have enclosed a graph of the three choices.

y = x^3 + 4 is red

y = 2x^3 + 4 is blue

y = (1/2) x^3 + 4 is green. The green one is the one you want.

6 0
3 years ago
Read 2 more answers
PLz help I will give brainliest!!!!! and extra points
Natalija [7]

Hey there!

<u></u>

The answer to your question is 95.55<u></u>

<u></u>

<u>Formulas:</u>

<u></u>

<em>Area of semi-circle = </em>\frac{1}{2}(\pi r^2)<em></em>

<em>Area of rectangle = </em>lw<em></em>

<em>Area of triangle = </em>\frac{bh}{2}<em></em>

<em></em>

<u>Now solve:</u>

<em>semi-circle</em>

\frac{1}{2}\pi3^2

\frac{1}{2}\pi9

4.5\pi

<em>(We will use 3.14 as approx. for pi)</em>

<em />4.5 * 3.14\\23.55

<em>rectangle</em>

10(6)\\60

<em>triangle</em>

<em />\frac{4(6)}{2}<em />

<em />\frac{24}{2} \\12<em />

<em>Now add them all together:</em>

<em />23.55+60+12\\95.55<em />

<em />

Have a terrificly amazing day!

<em />

3 0
3 years ago
The parking space shown on the right has an area of 216 ft². A custom truck has rectangular dimensions of 12.1 ft by 3.6 ft. Can
mart [117]

Answer:

• Yes, the area of the truck is less than the area of the parking space.

,

• The missing dimension of the parking space is 12 ft.

Explanation:

The area of the parking space = 216 ft²

Part A

The dimensions of the custom truck = 12.1 ft by 3.6 ft.

To determine if the truck can fit into the space, we calculate the area of the truck.

\begin{gathered} \text{Area of the truck}=12.1\times3.6 \\ =43.56ft^2 \end{gathered}

Since the area of the truck is less than the area of the parking space, the truck will fit into the space.

Part B

The parking space is in the shape of a parallelogram.

\text{Area of a parallelogram=Base x Perpendicular Height}

Given:

• Area = 216 ft²

,

• Base = b ft

,

• Perpendicular Height = 18 ft

We then have:

\begin{gathered} 216=b\times18 \\ 18b=216 \\ b=\frac{216}{18} \\ b=12\text{ ft} \end{gathered}

The missing dimension of the parking space is 12 feet.

7 0
2 years ago
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