The answer is b i hope this right to u
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375
Answer:
i can't help with this specific queshtion but i do have tow say to things 1. when you post something like this make sure to crop out anything that people can see your info or anything like block out the tabs someone could see that and use it for evil be careful with this, second i do aleks to.
Step-by-step explanation:
im sorry i could not help you in the way you wanted but i hop you will be safe now!
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Have a nice day!
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,
y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
Answer:
90. 04987916
Step-by-step explanation:
Let HI be a
and GH be c
and GI be b
and <GHI be B
Using the law of Cosines,
b^2= -2ac cos (B) + c^2 + a^2
= -2(42)(60) cos (123)+60^2+42^2
= -5040 cos (123) +3600+1764
= -5040(-0. 544639035) +5364
= 2744. 980736+5364
b^2= 8108. 980736
b= Sqrt ( 8108. 980736)
b= 90. 04987916
