The answer is b i hope this right to u
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375
Answer:
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Step-by-step explanation:
im sorry i could not help you in the way you wanted but i hop you will be safe now!
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Have a nice day!
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,
y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
Answer:
90. 04987916
Step-by-step explanation:
Let HI be a
and GH be c
and GI be b
and <GHI be B
Using the law of Cosines,
b^2= -2ac cos (B) + c^2 + a^2
= -2(42)(60) cos (123)+60^2+42^2
= -5040 cos (123) +3600+1764
= -5040(-0. 544639035) +5364
= 2744. 980736+5364
b^2= 8108. 980736
b= Sqrt ( 8108. 980736)
b= 90. 04987916