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otez555 [7]
3 years ago
15

7x+4y=16 find the slope and y intercept

Mathematics
1 answer:
docker41 [41]3 years ago
6 0

Answer:

7x is the slope

Step-by-step explanation:

And the y intercept is 16

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I got 63,000 because it simplifies to 45*35*4
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Sara bought a used car for $10,000. She learned from online that the value of a car depreciated 15% per year. What is the formul
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Answer:

Step-by-step explanation:

Value of Sam's car after t years =

==10000*(1-\frac{15}{100})^{t}\\\\=10000*(\frac{85}{100})^{t}\\\\=10000*(0.85)^{t}

Value of Sam's car in 5 years=

=10000*(0.85)^{5}\\\\=10000*0.4437\\\\

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Can someone help me with this If 5y*2=80 y=?
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<span>If 5y*2=80 then y is equal to 8</span>
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Which ordered pair is the solution to the system of linear equations y = -7x + 2 and y = 9x - 14?
lisabon 2012 [21]
Y = -7x + 2
y = 9x - 14

-7x + 2 = 9x - 14
14 + 2 = 9x + 7x
16 = 16x
1 = x

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3 years ago
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Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
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