Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
Answer:
-3 and 4
Step-by-step explanation:
-3 x 4= -12 and -3 + 4= 1
Answer:
7∠82°
Step-by-step explanation:
Well angle 6 and 7 are complementary angles, meaning they both add up to 180°.
So we do 180 - 98 which is 82°.
Answer:
3 cm and 1.75 cm
Step-by-step explanation:
the numbers have to coincide with the ones being compared in the same amount. like 3×2=6 and its the same with 1.75×2=3.50
