The perimeter is equal to 2(width) + 2(length). let's call the width w and the length L.
so 32 = 2w + 2L
the width is given as 2 meters less than the length, so w = L - 2
32 = 2(L - 2) + 2L
32 = 2L - 4 + 2L
32 = 4L - 4
36 = 4L
9 = L
so our length is 9 meters.
w = L - 2
w = 9 - 2
w = 7
so our width is 7 meters.
The question ask to find the angle between the given vector to the nearest tenth of a degree and base on the value or the coordinates of each vector, the possible value of the angle base on the said vectors is 1.8 degree. I hope you are satisfied with my answer and feel free to ask for more
Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16, we get 32+41-16+16=73
Part A:
There are 25 blocks for the length, and the length of each is 5.5 inches. 5.5x25=137.5
There are 9 blocks for the height, and each is 2.75 inches. 2.75x9=24.75
Since we're trying to find how much longer the length is to the width, we find the difference. 137.5-24.75=112.75
So part A answer is <em><u>112.75 (or 112¾)</u></em>
Part B:
We know the length is 137.5 and the height is 24.75. To find how many times longer the length is, we need to divide to see how many 24.75 can go into 137.5.
137.5÷24.75=5.55
So the answer to part B is <u><em>5.55. Given the context, the answer would probably be 5, because that's how many entire height can fit.</em></u>
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Sorry if it's wrong lol
