Answer: x = 0
Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.
F(x) = 11x² + 5x
f'(x) = 22x + 5
Hence,
f'(9) = (22 * 9) + 5 = 198 + 5 = 203
Answer: 3 cofficients are there ( 5, 2, and 6).
Answers:
a = 2
b = 3
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Explanation:
Plug in x = 0 and y = 2 to find that
y = a*b^x
2 = a*b^0
2 = a*1
2 = a
a = 2
Then plug in x = 3 and y = 54 to determine the value of b
y = a*b^x
y = 2*b^x
54 = 2*b^3
2b^3 = 54
b^3 = 54/2
b^3 = 27
b = (27)^(1/3)
b = 3
So we have y = a*b^x update to y = 2*3^x
Answer:
6 cm
Step-by-step explanation:
If you use Tangent-secant product (chapter reference), AB/AC = AD/AB so 4/2 = AD/4. AD = 8, CD = AD - AC = 8 - 2 = 6 cm.
